The first can be any one of 15 cheerleaders. For each of those . . .
The second can be any one of the remaining 14. For each of those . . .
The third can be any one of the remaining 13. For each of those . . .
The fourth can be any one of the remaining 12. For each of those . . .
The fifth can be any one of the remaining 11.
The total number of permutations is (15 x 14 x 13 x 12 x 11) = 360,360 .
But . . .
Once you have five people on a squad, the order in which they were chosen doesn't matter.
If you have A-B-C-D-E standing there, it's the same group of kids as A-B-C-E-D. So for each
squad of five, they could have been chosen in (5 x 4 x 3 x 2 x 1) = 120 different ways.
There are 360,360 different ways to choose squads of 5, but only (360360/120) = 3,003 different squads.
6,375,600
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
I think he is the chosen one.We have chosen to watch King Kong.He was never chosen to be part of the cheerleading team.
There are 11880 ways.
The Rooney family is classy. I can't find a reason but at one time they did. They were called the Steelerettes (steelerettes.com) and were a squad chosen from a local junior college. Once the junior college had their own football team, the Steelerettes disbanded. They were the official squad from 1961-1970. The Steelers were actually one of the first teams to ever have cheerleaders. They were named (are you ready for this?) The Steelerettes. How clever. They were basically a gimmick created to take attention away from how awful the team was. The squad only stuck around for about 8 years (61-69) before they were disbanded. As for why they don't have a squad now, can you imagine trying to find a group of attractive women who would be willing to bounce around in short skirts in the middle of December in Pittsburgh? They'd have to be crazy.
There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
Students should aspire to achieve the title of "expert" or "specialist" in their chosen field of study.
randomly
Any 5 from 7 is (7 x 6)/2 ie 21.
C105 = 10 ! / (5!x(10-5)!) = 10! /5!2 = 252
Well, honey, there are 30 students in the class, and you want to choose a group of 3. So, you're looking at a classic combination situation. The formula for combinations is nCr = n! / r!(n-r)!, so in this case, it's 30C3 = 30! / 3!(30-3)! = 4060 ways to choose those 3 lucky students. It's like picking the winning lottery numbers, but with fewer tears and more math.