answersLogoWhite

0

Any 4 from 26 in any order is (26 x 25 x 24 x 23) = 358800. if You can't use ACBD and ABCD then the answer is 14950

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

How many 3 letter arrangements are possible from 26 letters if no letter can be repeated?

The number is 26*25*24 = 15600.


What is the no of linear arrangements of the four letters in CALL is?

To find the number of linear arrangements of the letters in "CALL," we need to consider the repetitions of letters. The word "CALL" has 4 letters where 'L' appears twice. The formula for arrangements of letters with repetitions is given by ( \frac{n!}{p1! \times p2! \times \ldots} ), where ( n ) is the total number of letters and ( p1, p2, \ldots ) are the frequencies of each repeated letter. Therefore, the number of arrangements is ( \frac{4!}{2!} = \frac{24}{2} = 12 ). Thus, there are 12 distinct arrangements of the letters in "CALL."


If a code contains 4 letters and 2 numbers how many possible outcomes are there?

If the numbers and letters can be repeated then there are 45,697,600 possible outcomes. If the letters and numbers can not be repeated there are 32,292,000 possible outcomes.


How many different arrangements can be made with the letters from the word GRAPHICS?

64 different arrangements are possible.


Can you list all the possible arrangements of the letters N O and T?

The possible arrangements of the letters N, O and T are :don'twontnotsnotrotknotnothing.......... and more....... just take a clue jeez........


How many 2 letter arrangements are possible from 26 letters if no letter can be repeated?

Any 2 from 26 = 26 x 25 = 650 if ab and ba are regarded as separate, otherwise 325.


How many arrangements of the letters BOX are possible if you use each letter only once in each arrangement?

The word "BOX" consists of 3 distinct letters. The number of arrangements of these letters can be calculated using the factorial of the number of letters, which is 3! (3 factorial). Therefore, the total number of arrangements is 3! = 3 × 2 × 1 = 6. Thus, there are 6 possible arrangements of the letters in "BOX."


How many five-letter arrangements are possible from the five letters MAMMM?

Five


How many words can you make out of the letters helgerv?

Without allowing repeated letters there are 38 possible words:GEEGHEEGLEELEGEREGERGREEVERGEHEELHELVEHEREEELLEELEERREELELVERLEVERREVELEREREEEVERVEEREVEVEEGELLEGERGREGVEGHEEHHERLLEHRHERELLEVERREREV


How many four-letter arrangements can be made of the letters a c e f and h if there is repetition of letters?

There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.


How many arrangements of the letters help are possible?

24, none of which are other actual words.


How many 4letter words can be made out of the word kingstown?

Some four letter words that can be made from the letters in Kingston are:ginsgistgowninksinnsintoionskingkinskitsknitknotknownitsnowtoinkownssignsingsinkskinskitsnitsnotsnowsongsownstowswigtinstogstongtonstowntowstwigtwinwigswingwinkwinowinswistwitswokswon't