(Assuming 100 is 100 degrees)
cos 100 degrees is equal to - sin 10 degrees.
In radians, this is - sin (pi/18).
Approximating pi as 22/7, this is - sin (11/63)
Using four terms of a Taylor series, this is approximately:
- (11/63) + (11/63)^3 /6 - (11/63)^5 / 120 + (11/63)^7 / 5040.
- (11/63) + (11^3/63^3) /6 - (11^5/63^5) / 120 + (11^7/63^7) / 5040.
Rewriting the fractions with the common denominator 63^7:
- (11*63^6/63^7) + (11^3*63^4/63^7) /6 - (11^5*63^2/63^7) / 120 + (11^7/63^7) / 5040.
Rewriting again with common denominators of 5040:
- 5040*(11*63^6/63^7)/5040 + 840*(11^3*63^4/63^7)/5040 - 42*(11^5*63^2/63^7) / 5040 + (11^7/63^7) / 5040.
Now add it all up:
[- 5040*11*63^6 + 840*11^3*63^4 - 42*11^5*63^2 + 11^7] / (5040*63^7)
Now, some seriously long multiplication gives:
(- 3466302962466960 + 17612440516440 - 26846879598 + 19487171) / 19852462421401680
Some really easy addition:
-3448717349342947 / 19852462421401680
And finally, do the long division:
-0.17371735939 ... and so on.
The actual value is -0.17364817766693034885171662676931
So, I got 3 decimal places right. Maybe use a better approximation of pi (like 355/113) and more terms of the Taylor series. But you get the picture.
This can be done on a graphing calculator by making sure you have your calculator in degrees mode, and then tentering the cos(23). You get an answer of 0.9205048535.
Cos is short for Cosine ( Complementary Sine) Similrly Sin is short for Sine Tan is short for Tangent.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
First make sure the calculator is in 'Degree Mode'. Then press 'Cos' , followed by the angle in degrees, say '60' degrees, then press equals (=), and the answer should read '0.5'. NB If the calculator is in 'Radiuan Mode' Press 'Cos' followed by ' pi' divide '3' . Then equals (=) , again the answer should be '0.5'.
To solve the equation 2cos(x) + cos(x) - 1 = 0, we first combine like terms to get 3cos(x) - 1 = 0. Then, we isolate the cosine term by adding 1 to both sides to get 3cos(x) = 1. Finally, we divide by 3 to solve for cos(x), which gives cos(x) = 1/3. Therefore, x = arccos(1/3) or approximately 70.53 degrees.
Isolate cos (t): cos(t)=1/3. Use a calculator from here because the answer is not an integer or a simple number.
cos(60) = 0.5 The simplest way is to use a calculator.
For any calculator Sec(Secant) = 1/Cos Csc (Cosecant) = 1/ Sin Cot (Cotangent) = 1/Tan
This can be done on a graphing calculator by making sure you have your calculator in degrees mode, and then tentering the cos(23). You get an answer of 0.9205048535.
Press the button labeled "COS"
Cos is short for Cosine ( Complementary Sine) Similrly Sin is short for Sine Tan is short for Tangent.
It is usually [Shift] [cos] though on some calculators it may be [2ndF] [cos] The arc cos function is often written as cos-1 or acos, and on most calculators is written above the button to press; the colour of the text used to write it usually matches up with the key needed to press before the cos button. On Casio calculators, it is [shift][cos] with the shift key labelled in yellow, and cos-1 written in yellow. On a Texas Instruments calculator it is [2nd] [cos] with the 2nd key labelled in blue and the cos-1 written in blue. On a Hewlett Packard calculator it is [<up_arrow_pointing_left>][cos] with the up_arrow_pointing left a white key with a black arrow and ACOS written in white above the cos button.
Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.
cos(-100 degrees)
Please do.
The question contains an expression but not an equation. An expression cannot be solved.
It is labeled as "cos-1" on the calculator. But arcosine and inverse cosine are just two names for the same thing.