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y=tanx cannot be expressed as a Fourier series, since it has infinite number of infinite discontinuity.
Dirichlet’s condition or the sufficient condition for a function f(x) to be expressed as a Fourier series.
- f(x) is single valued, finite and periodic.
- f(x) has a finite number of finite discontinuities.
- f(x) has a finite number of maxima and minima.
- f(x) has no infinite discontinuity.
What else can I help you with?
How can arccot of tanx be simplified?
There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
How do you solve tan squared theta - tan theta equals 0?
Let x = theta, since it's easier to type, and is essentially the same variable. Since tan^2(x)=tan(x), you know that tan(x) must either be 1 or zero for this statement to be true. So let tan(x)=0, and solve on your calculator by taking the inverse. Similarly for, tan(x)=1
Is tan squared x equal tan x squared?
Yes. Both expressions are the same.
What is the period of tan x?
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
What angle do you need for a gradient of 1 in 20?
If the angle is x radians, then tan(x) = 1/20 = 0.05 So x = tan-1(0.05) = 0.04996 radians = 2.86 degrees (approx)
Differences between full range Fourier series and a Half range Fourier series?
half range--- 0 to x full range--- -x to x
How you learn fourier series in online?
x
Sec x times sin x divided by tan x?
1 (sec x)(sin x /tan x = (1/cos x)(sin x)/tan x = (sin x/cos x)/tan x) = tan x/tan x = 1
What is the answer to cot squared x - tan squared x equals 0?
cot2x-tan2x=(cot x -tan x)(cot x + tan x) =0 so either cot x - tan x = 0 or cot x + tan x =0 1) cot x = tan x => 1 / tan x = tan x => tan2x = 1 => tan x = 1 ou tan x = -1 x = pi/4 or x = -pi /4 2) cot x + tan x =0 => 1 / tan x = -tan x => tan2x = -1 if you know about complex number then infinity is the solution to this equation, if not there's no solution in real numbers.
Which expression has the same value as tan(-x) for all values for x?
tan(-x) = -tan(x)
What is the Fourier transform of the function f(x) 1/r?
The Fourier transform of the function f(x) 1/r is 1/k, where k is the wave number.
Sin x Tan x equals Sin x?
No. Tan(x)=Sin(x)/Cos(x) Sin(x)Tan(x)=Sin2(x)/Cos(x) Cos(x)Tan(x)=Sin(x)
How can arccot of tanx be simplified?
There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
What does cos divided by sin equal?
tan x
What is tan x csc x?
tan(x)*csc(x) = sec(x)
What is cos x tan x simlpified?
The definition of tan(x) = sin(x)/cos(x). By this property, cos(x)tan(x) = sin(x).
What is the fourier transform of Tan function?
tanx = 2*(sin2x - sin4x + sin6x - ... )However, be warned that this series is very slow to converge.
