-1 < sine(theta) < 1 so sine(theta) cannot be 3125
That depends on the value of the angle, theta. csc is short for "cosecans", and is the reciprocal of the sine. That is, csc theta = 1 / sin theta.
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
By converting cosecants and secants to the equivalent sine and cosine functions. For example, csc theta is the same as 1 / sin thetha.
Tangent (theta) is cosine / sine, or Y / X.Tangent (theta) is 40 / 58Theta = 34.6 degreesSince we are dividing cosine by sine, the hypotenuse does not matter as it cancels out.
-1 < sine(theta) < 1 so sine(theta) cannot be 3125
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.
Cosine squared theta = 1 + Sine squared theta
The sine theta of an angle (in a right triangle) is the side opposite of the angle divided by the hypotenuse.
cosine (90- theta) = sine (theta)
That is not a question.
sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)
near zero
The sine of an angle theta that is part of a right triangle, not the right angle, is the opposite side divided by the hypotenuse. As a result, you could determine the hypotenuse by dividing the opposite side by the sine (theta)...sine (theta) = opposite/hypotenusehypotenuse = opposite/sine (theta)...Except that this won't work when sine (theta) is zero, which it is when theta is a multiple of pi. In this case, of course, the right triangle degrades to a straight line, and the hypotenuse, so to speak, is the same as the adjacent side.
Yes. (Theta in radians, and then approximately, not exactly.)