0
= tan ^ -1 (0.55431) = approximately 29 degrees
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What is Arctan 0.55431?
ArcTan is another name for ;Inverse Tan' or 'Tan^*-1) Hence ArcTan(0.55431) = 29.00004157 degrees. Effectively 29 degrees.
The two sides of a right triangle are of length 19 and 63 What is the measure of either of the acute angles in degrees?
Assuming that neither of the given sides is the hypotenuse, then if A is one of the acute angles, tan(A) = 19/63 So A = arctan(19/63) = 16.8 degrees. The other acute angle is 73.2 deg.
Do you know about the terms function and relation in trigonometry?
Trigonometric functions are periodic so they are many-to-one. It is therefore important to define the domains and ranges of their inverses in such a way the the inverse function is not one-to-many. Thus the range for arcsin is [-pi/2, pi/2], arccos is [0, pi] and arctan is (-pi/2, pi/2). However, these functions can be used, along with the periodicities to establish relations which extend solutions beyond the above ranges.
Find the exact value of the expression sinarctan-12?
Assume the angle u takes place in Quadrant IV. Let u = arctan(-12). Then, tan(u) = -12. By the Pythagorean identity, we obtain: sec(u) = √(1 + tan²(u)) = √(1 + (-12)²) = √145 Since secant is the inverse of cosine, we have: cos(u) = 1/√145 Therefore: sin(u) = -√(1 - cos²(u)) = -√(1 - 1/145) = -12/√145 Otherwise, if the angle takes place in Quadrant II, then sin(u) = 12/√145
Tangentk equals 0.575 find angle k?
Well, darling, if tangent k equals 0.575, then angle k is approximately 29.74 degrees. Just remember to use your trusty calculator and make sure it's in the correct mode before you go crunching those numbers. Happy calculating, honey!
