The length, or magnetude, of the vector is the square root of (6^2 + 8^2), or 10. The angle of inclination is tan-1 of (8/6), or 53.13 degrees.
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at least 25 bundles With an average of 3 bundles per square(100 square feet) an 8 square roof would need 24 bundles plus 1 for cuts and shorts.
Negatives cause no problem: log10x = -3 means x = 10-3 = 0.001 It doesn't make sense, though, to FIND the logarithm of a negative number: log10(-8) = ???? (unless you know about complex numbers . . . )
The current standard for stairs in the US is a maximum of 7" per riser.10' is 120", divided by 7" is just over 17,but since the maximum allowable is 7" you're going to have to have 18 risers at 6 2/3"Don't panic, your framing square has one leg divided into 12ths,8/12 = 2/3
The diagonal measurement of an 8 ft square is: 11.31 feet.
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)
Don't tell me you are in class!
8 in * 10 ft = 8 in * 10 ft = 960 square inches or 8 in * 10 ft = 2/3 ft * 10 ft = 62/3 square feet
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
10 ft x 8 ft = 80 square feet.
8ft * 10 ft = 8*10 sq ft = 80 sq ft
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
The diagonal = the square root of (6 squared + 8 squared) 6 squared+8squared = 100 the square root of 100 = 10 so the length of the diagonal is 10. The above used Pythagoras' theorem which says the square on the diagonal is equal to the sum of the squares on the other two sides.
Assuming the room is 8 ft by 10 ft (the question does not say so), the area would be 8*10 = 80 square feet
8 ft x 10 ft = 80 ft2 or 80 square feet.
10 x 8 = 80 square feet.