Don't tell me you are in class!
18.9 feet
Ah, what a lovely question! To find the length of the diagonal of a square, we can use the Pythagorean theorem. Since we have a 10 by 10 ft square, both sides are equal, making it a right triangle with legs of 10 ft each. By using a^2 + b^2 = c^2, where a and b are the legs and c is the diagonal, we find that the diagonal is √(10^2 + 10^2) = √200 ft.
10 ft x 8 ft = 80 square feet.
20 ft
The diagonal measurement of an 8 ft square is: 11.31 feet.
If you mean a rectangle then its diagonal using Pythagoras; theorem is 2 times the square root of 41 or about 12.806 feet rounded to 3 decimal places.
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
Don't tell me you are in class!
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
Around 17.8. I did this with cossin, but check the answer with a calculator
18.9 feet
18.9 feet
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
The diagonal is ~16.97 feet.
Diagonal = 10 meters.