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What is the maximum value of X minus the minimum value of X?
The maximum value of X minus the minimum value of X is calculated by subtracting the minimum value from the maximum value. This difference represents the range of the values of X. If you have specific values for X, you can determine the maximum and minimum values and then compute this difference accordingly.
How do you find maximum revenue using quadratic equations?
Suppose the revenue equation is of the form R = ax2 + bx + c where a, b and c are constants and x is the variable. To have a maximum, either a must be negative or x must lie within fixed limits. If a is negative then the maximum revenue is attained when x = -b/(2a). That is, find the value of R when x = -b/(2a). If a is positive, then find the value of R when x is at each end point of its domain. One of them will be larger and that is the maximum value of the revenue.
What is the maximum possible value of x?
If x is the unknown or variable in an equation it can have many possible maximum or minimum values
What is the maximum value of 6x 5y in the feasible region?
To find the maximum value of (6x + 5y) in the feasible region, we typically need the constraints that define that region (such as inequalities involving (x) and (y)). Without those constraints, we can't determine the maximum. Generally, the maximum occurs at one of the vertices of the feasible region formed by the intersection of the constraint lines. If you provide the specific constraints, I can help find the maximum value.
How do you find out instantaneous velocity and maximum height?
Take the derivative of the function.By plugging a value into the derivative, you can find the instantaneous velocity.By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.Example:Find the instantaneous velocity at x = 3 and find the maximum height.f(x) = -x2 + 4f'(x) = -2xf'(3) = -2*3 = -6So the instantaneous velocity is -6.0 = -2x0 = xSo the maximum height occurs at x = 0f(0) = -02 + 4 = 4So the maximum height is 4.
How do you find the range and domain of a graph function?
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
How do you find minimum and maximum value of calculus?
For the function y = x^(3) + 6x^(2) + 9x Then dy/dx = 3x^(2) + 12x + 9 At max/min dy/dx = 0 Hence 3x^(2) + 12x + 9 = 0 3(x^(2) + 4x + 3) = 0 Factor (x + 1)(x + 3) = 0 Hence x = -1 & x = -3 are the turning point (max/min) To determine if x = 0 at a max/min , the differentiate a second time Hence d2y/dx2 = 6x + 12 = 0 Are the max/min turning points. Substitute , when x = -1 6(-1) + 12 = (+)6 minimum turning point . x = -3 6(-3) + 12 = -6 maximum turning point. When x = positive(+), then the curve is at a minimum. When x = negative (-), then the curve is at a maximum turning point. NB When d2y/dx2 = 0 is the 'point of inflexion' , where the curve goes from becoming steeper/shallower to shallower/steeper. So when d2y/dx2 = 6x + 12 = 0 Then 6x = -12 x = -2 is the point of inflexion. NNB When differentiating the differential answer gives the steeper of the gradient. So if you make the gradient zero ( dy/dx = 0) , there is no steepness, it is a flat horizontal line
What is the maximum value of X minus the minimum value of X?
The maximum value of X minus the minimum value of X is calculated by subtracting the minimum value from the maximum value. This difference represents the range of the values of X. If you have specific values for X, you can determine the maximum and minimum values and then compute this difference accordingly.
How do you find maximum revenue using quadratic equations?
Suppose the revenue equation is of the form R = ax2 + bx + c where a, b and c are constants and x is the variable. To have a maximum, either a must be negative or x must lie within fixed limits. If a is negative then the maximum revenue is attained when x = -b/(2a). That is, find the value of R when x = -b/(2a). If a is positive, then find the value of R when x is at each end point of its domain. One of them will be larger and that is the maximum value of the revenue.
What direction does each of the yaxis run?
up and down. the x goes left and right
F(x) = | sin 3x | -3 find the maximum and minimum value?
if you have any doubts ask
What is the maximum value that the graph of ycosx assume?
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
What is The sum of maximum value of sin and minimum value of cos?
The maximum value of the sine function, (\sin(x)), is 1, while the minimum value of the cosine function, (\cos(x)), is -1. Therefore, the sum of the maximum value of sine and the minimum value of cosine is (1 + (-1) = 0).
What is the maximum possible value of x?
If x is the unknown or variable in an equation it can have many possible maximum or minimum values
What is the maximum value of 6x 5y in the feasible region?
To find the maximum value of (6x + 5y) in the feasible region, we typically need the constraints that define that region (such as inequalities involving (x) and (y)). Without those constraints, we can't determine the maximum. Generally, the maximum occurs at one of the vertices of the feasible region formed by the intersection of the constraint lines. If you provide the specific constraints, I can help find the maximum value.
How do you find out instantaneous velocity and maximum height?
Take the derivative of the function.By plugging a value into the derivative, you can find the instantaneous velocity.By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.Example:Find the instantaneous velocity at x = 3 and find the maximum height.f(x) = -x2 + 4f'(x) = -2xf'(3) = -2*3 = -6So the instantaneous velocity is -6.0 = -2x0 = xSo the maximum height occurs at x = 0f(0) = -02 + 4 = 4So the maximum height is 4.
What is the limit of sin x?
Sin(x) has a maximum value of +1 and a minimum value of -1.
