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What is the exact value of sin 255?
To find the exact value of sin 255°, we can use the sine subtraction formula. Since 255° = 270° - 15°, we can express it as: [ \sin(255°) = \sin(270° - 15°) = \sin(270°) \cos(15°) - \cos(270°) \sin(15°. ] Knowing that (\sin(270°) = -1) and (\cos(270°) = 0), we have: [ \sin(255°) = -1 \cdot \cos(15°). ] Thus, the exact value of (\sin(255°) = -\cos(15°)).
What is the value of cos2 67-sin2 23?
To find the value of ( \cos^2 67^\circ - \sin^2 23^\circ ), we can use the identity ( \cos^2 \theta = 1 - \sin^2 \theta ). Since ( \sin 23^\circ = \cos 67^\circ ) (because ( 23^\circ + 67^\circ = 90^\circ )), we have ( \sin^2 23^\circ = \cos^2 67^\circ ). Thus, ( \cos^2 67^\circ - \sin^2 23^\circ = \cos^2 67^\circ - \cos^2 67^\circ = 0 ). Therefore, the value is ( 0 ).
Is sin 2x equals 2 sin x cos x an identity?
YES!!!! Sin(2x) = Sin(x+x') Sin(x+x') = SinxCosx' + CosxSinx' I have put a 'dash' on an 'x' only to show its position in the identity. Both x & x' carry the same value. Hence SinxCosx' + CosxSinx' = Sinx Cos x + Sinx'Cosx => 2SinxCosx
What is the value of sin40sin50?
The value of ( \sin 40^\circ \sin 50^\circ ) can be simplified using the product-to-sum identities. Specifically, it can be expressed as: [ \sin A \sin B = \frac{1}{2} [\cos(A - B) - \cos(A + B)] ] Substituting ( A = 40^\circ ) and ( B = 50^\circ ): [ \sin 40^\circ \sin 50^\circ = \frac{1}{2} [\cos(40^\circ - 50^\circ) - \cos(40^\circ + 50^\circ)] = \frac{1}{2} [\cos(-10^\circ) - \cos(90^\circ)] = \frac{1}{2} [\cos(10^\circ) - 0] = \frac{\cos(10^\circ)}{2} ] The approximate numerical value is about ( 0.4848 ).
Find out value of sin 45 cos 45 - sin 230?
Assuming that the angles are all stated in degrees: sin(45) = cos(45) = 1/2 sqrt(2) sin(45) cos(45) = (1/2)2 x (2) = 1/2 sin(230) = - 0.7660444 sin(45) cos(45) - sin(230) = 0.5 + 0.7660444 = 1.2660444 (rounded)
What is the maximum value that the graph of ycosx assume?
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
What is the maximum value of cos square x - sin square x?
1
What is the limit of sin x?
Sin(x) has a maximum value of +1 and a minimum value of -1.
What is the value of sin A plus cos Acos A (1-cos A) when tan A 815?
When tan A = 815, sin A = 0.9999992 and cos A = 0.0012270 so that sin A + cos A*cos A*(1-cos A) = 1.00000075, approx.
What is the exact value of sin 255?
To find the exact value of sin 255°, we can use the sine subtraction formula. Since 255° = 270° - 15°, we can express it as: [ \sin(255°) = \sin(270° - 15°) = \sin(270°) \cos(15°) - \cos(270°) \sin(15°. ] Knowing that (\sin(270°) = -1) and (\cos(270°) = 0), we have: [ \sin(255°) = -1 \cdot \cos(15°). ] Thus, the exact value of (\sin(255°) = -\cos(15°)).
Find the value of a if tan 3a is equal to sin cos 45 plus sin 30?
If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.
F(x) = | sin 3x | -3 find the maximum and minimum value?
if you have any doubts ask
Verify that sin minus cos plus 1 divided by sin plus cos subtract 1 equals sin plus 1 divided by cos?
[sin - cos + 1]/[sin + cos - 1] = [sin + 1]/cosiff [sin - cos + 1]*cos = [sin + 1]*[sin + cos - 1]iff sin*cos - cos^2 + cos = sin^2 + sin*cos - sin + sin + cos - 1iff -cos^2 = sin^2 - 11 = sin^2 + cos^2, which is true,
How do you prove this trigonometric relationship sin3A equals 3sinA cos 2 A - sin 3 A?
sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)
What trigonometric value is equal to cos 47?
The trigonometric value equal to cos 47° is sin(90° - 47°), which is sin 43°. This is based on the co-function identity in trigonometry, where the cosine of an angle is equal to the sine of its complement. Therefore, cos 47° = sin 43°.
What is the value of cos2 67-sin2 23?
To find the value of ( \cos^2 67^\circ - \sin^2 23^\circ ), we can use the identity ( \cos^2 \theta = 1 - \sin^2 \theta ). Since ( \sin 23^\circ = \cos 67^\circ ) (because ( 23^\circ + 67^\circ = 90^\circ )), we have ( \sin^2 23^\circ = \cos^2 67^\circ ). Thus, ( \cos^2 67^\circ - \sin^2 23^\circ = \cos^2 67^\circ - \cos^2 67^\circ = 0 ). Therefore, the value is ( 0 ).
What is the numerical value of cos 35 x sin 24?
In degrees? cos(35˚) = .81915, sin(24˚) = .40673;cos(35˚) * sin(24˚) = .33318In radians? cos(35) = -.90367, sin(24) = -.90558;cos(35) * sin(24) = .81836A calculator will achieve these results faster than wiki.answers. 9 times out of 10, at least.:-)
