answersLogoWhite

0


Best Answer

27 28 29 30

User Avatar

Wiki User

โˆ™ 2009-04-11 02:35:21
This answer is:
๐Ÿฆƒ
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards

J's study guide

1 card

What is the name of Steve on minecraft's name

โžก๏ธ
See all cards

Steel Tip Darts Out Chart

96 cards

170

169

168

167

โžก๏ธ
See all cards

Add your answer:

Earn +20 pts
Q: Find 4 consecutive integers whose sum is 114?
Write your answer...
Submit
Related questions

What integers are four consecutive integers whose sum is 114.?

27 + 28 + 29 + 30 = 114


4 consecutive even integers whose sum is -114?

118


Find four consecutive integers whose sum is 114?

The numbers are 27, 28, 29 and 30.


Find 3 consecutive even integers whose sum is -114?

117


Consective even integers Find three consective integers whose sum is 114?

The consecutive odd integers for 114 are 37, 38 and 39.


What are 4 consecutive integers whose sum is 114?

The integers are 27, 28, 29 and 30.


What are 4 consecutive integers whose sum equals 114?

27+28+29+30=114


What are 4 consecutive integers for 114?

27 + 28 + 29 + 30 = 114


What is the sum of the three consecutive integers that equals 114?

The integers are 37, 38 and 39.


What is three consecutive integers whose sum is 117?

Three consecutive integers whose sum is 117 are 38, 39, and 40. N + (N+1) + (N+2) = 117 3N + 3 = 117 3N = 114 N = 38


What are four consecutive integers of 114?

27, 28, 29 and 30.


What are the Consecutive integers whose sum is 114?

27, 28, 29 and 30 is one set that meets the requirement. 37, 38 and 39 is another. There are many such sets.


What is the sum of two consecutive even integers is 114?

The numbers are 56 and 58.


What are four consecutive integers and the sum is 114?

27, 28, 29 and 30


What three consecutive numbers add up to 114?

114/3 = 38, so the three integers are 37, 38 and 39.


The sum of three consecutive integers is -114 What are the integers?

Let the integers be x, (x+1) and (x+2) Since, x+(x+1)+(x+2) = -114, by solving the equation for x, we get that, x = -37 Hence the integers are -37, -36 and -35


What is the larger of two consecutive even integers if their sum is 226?

The larger is 114, and the other is 112.


The sum of three consecutive even integers is 114?

Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40. Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114 So 3n+6=114 and 3n=108 so n=36 then next two numbers must be 38 and 40 since they are consecutive even integers.


What are the first ten consecutive composite numbers?

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123


What are the five consecutive composite numbers from 101 to 200?

The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.


What are four consecutive integers of one hundred fourteen?

114/4 = 28.5 So the 4 numbers are 27, 28, 29 and 30


What 3 consecutive numbers come out to 114?

37+38+39=114


What are the 13 consecutive composite numbers in the integers 1-200?

114 115 116 117 118 119 120 121 122 123 124 125 126


The sum of two consecutive even integers is 226 What is the larger integer?

114.As we know that the numbers are 2 consecutive even integers, we know that one number will be 2 larger than the other. We can use this to solve the problem with algebra:Where x is the smaller number,x + (x + 2) = 2262x + 2 = 2262x = 224x = 112Therefore the larger integer is 112 + 2 = 114


What are 3 consecutive integers that equal 114?

Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.