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If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
As a straight line equation: y = -3x+18 in slope intercept form
It is: y-7 = 2(x-3) => y = 2x+1
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y = 2x - 1
y=2x+1
The answe iss..... 6
It is: y = 2x-6
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
y = 2x + 1.
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Slope: -5 Points: (6, 3) Equation: y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
Slope: -3 Point: (4, -5) Equation: y = -3x+7