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x^2(x + 2) - 1(x+2)

(x+2)(x-1)(x+1)

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Q: How do you factor. Px x4 - x3 2x2 - 4x - 8?
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What is the factor of X3 - 2x2 - 4x plus 8?

x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)


How do you factor x3 plus 2x2 plus 4x plus 8?

(x + 2)(x^2+4)


When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?

(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)


How do you factor x3 2x2 5x 4?

x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)


Factor the polynomial x3-2x2 plus x-2?

x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)


What is the factor of x3 plus x2 plus 4x plus 4?

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)


How do you factor Px x4 x3 2x2 4x 1?

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).


How do you factor x3 2x2 x 2 completely?

(x + 2)(x ^2 + 1)


Can you factor x3-64?

(x - 4)(x^2 + 4x + 16)


How do you find the x- coordinates of the turning points of y equals x3-2x2-5x plus 6?

Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)


X3 plus 6x2 - 4x - 24 factor completely?

x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)


Factor x3 plus 64?

64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)