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Q: How do you factor Px x4 x3 2x2 4x 1?
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How do you factor. Px x4 - x3 2x2 - 4x - 8?

x^2(x + 2) - 1(x+2) (x+2)(x-1)(x+1)


What is the factor of X3 - 2x2 - 4x plus 8?

x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)


How do you factor x3 plus 2x2 plus 4x plus 8?

(x + 2)(x^2+4)


When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?

(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)


How do you factor x3 2x2 5x 4?

x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)


Factor the polynomial x3-2x2 plus x-2?

x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)


What is the factor of x3 plus x2 plus 4x plus 4?

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)


How do you factor x3 2x2 x 2 completely?

(x + 2)(x ^2 + 1)


Can you factor x3-64?

(x - 4)(x^2 + 4x + 16)


How do you find the x- coordinates of the turning points of y equals x3-2x2-5x plus 6?

Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)


X3 plus 6x2 - 4x - 24 factor completely?

x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)


Factor x3 plus 64?

64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)