That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (1 plus or minus i times the square root of 69) divided by 7
x = 0.142857 repeating + 1.1866605518454392i
x = 0.142857 repeating - 1.1866605518454392i
where i is the square root of negative one.
(x + 5)(x^2 + 2x + 2)
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
(7x + 5)(x - 2)
20x2 - 3x + 10 does not have any real factors.
(11x - 2)(3x - 5)
(5x - 2)(x - 5)
21x2 + 27x - 30 = 3*(7x2 + 9x - 10) = 3*(7x2 - 5x + 14x - 10) =3*[x*(7x - 5) + 2*(7x - 5)] = 3*(7x - 5)*(x + 2)
7x2-9x-10 7*-10=-707x2-14x+5x-10=-70\........./.......\/7xx 2*7x...5x 2*57x(x-2)+5(x-2)=-70(x-2)(7x+5)=-70I forget how to do the rest. But I graphed it and the solution set is {-0.5,2}
NO!!!! Here is a table for multiplication/division of 'double (+/-) signs.'. (+)(+) = (+) (+)(-) = (-) (-)(+) = (-) (-)(-) = (+) Sometimes in higher level maths, you can have triple signs. Here is the table. (+)(+)(+) = (+)(+) = (+) (+)(-)(-) = (-)(+) = (-) (-)(+)(+) = (-)(+) = (-) (-)(-)(-) = (+)(-) = (-) It is irrelevant on the position of the 'sign'. NB If no sign is given, then read it as positive (+).
The GCF is 7. Divide both terms by 7. 7(x2 - 10)
Your answer is either: 2, 4, 5, or 10. The square root of one blonde = 1. 1 minus the cube of one blonde brain = 0. 0 plus one factor of 20 (factors of 20 are: 2, 4, 5, 10) = which ever factor you choose. :)
k = 7 x^4 - 5x^3 + 7x^2 + 3x - 10 = (x + 1)(x - 2)(x^2 - 4x + 5)