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Q: How do you factor 9x squared minus 64?

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x2-9x can be factored by taking x out of each term x(x-9)

(9x + 8)(9x - 8)

It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

(x + 3)(3x - 2)

x2-9x+8=0 has two solutions:x = 8x = 1

(x + 12)(x - 3)

9x2-9x-10 = (3x+2)(3x-5) when factored

(x + 2)(3x - 1)(3x + 1)

9x2 - 18x + 99(x2 - 2x + 1)==========

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

9x squared plus 16 = 0 factored is plus and minus 4/3 i.

That factors to 3x(3x - 1)

With the help of the quadratic equation formula

(5x + 1)(x - 2)

x2 - 9x + 20 = (x - 4)( x - 5)

x = -2/3,7/6

9x(x2+3x-10)

9(x2 - 2)

2x2-9x+4 = (2x-1)(x-4) when factored

Assuming it's a plus sign, that factors to (2x + 1)(x + 4)

9X2 = 3X(3X) Best I can see to factor here.

You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.

Type your answer here... 81

9x squared-15x squared = -6

(3x-4)(3x+4)