x(x - 13)(x - 1)
x(x - 13)(x - 1)
x(x - 1)(x - 13)
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
x(x + 9)(x + 5)
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
x3+27y3 = (x+3y) · (x2-3xy+9y2)
x2(x3 + 1) is the best you can do there.
x(x^2 + 2)
x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)
(x + 2)(x^2+4)