There are often multiple 'correct' dimensions for these problems. The most straight forward way to solve it is to list all the factors that, when multiplied, equal the area. Then from this list, cross out the factors that DON'T equal your perimeter. The remaining factors are your possible dimensions.
To find the perimeter you add and to find the area we multiply.
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
The dimensions for area are [L2]
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
you need length and width length multiply width = area length + length + width + width = perimeter
Type your answer here... give the dimensions of the rectangle with an are of 100 square units and whole number side lengths that has the largest perimeter and the smallest perimeter
Length + width = half the perimeter, but more info eg area, is needed.
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
To find the perimeter you add and to find the area we multiply.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
The dimensions for area are [L2]
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
Assuming that you want to minimise the perimeter, then use a square. Its side length is, of course, given by the square root of the area.