Q: How do you find the missing vector?

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The Resultant Vector minus the other vector

If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).

We get the Unit Vector

Missing....? But the answer to find the missing is normally either "algebra" or "find another equation to use."

If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.

Related questions

The Resultant Vector minus the other vector

If you assume the vector is only in two dimensions, you can find the missing y-component with Pythagoras' Theorem: y = square root of (magnitude2 - x2).

We get the Unit Vector

Divide the vector by it's length (magnitude).

To find the acceleration of a particle using the vector method, you can use the equation a = r x (w x v), where "a" is the acceleration, "r" is the position vector, "w" is the angular velocity vector, and "v" is the velocity vector. The cross product (x) represents the vector cross product. By taking the cross product of the angular velocity vector with the velocity vector and then multiplying the result by the position vector, you can find the acceleration of the particle.

Missing....? But the answer to find the missing is normally either "algebra" or "find another equation to use."

reverse process of vector addition is vector resolution.

If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.

The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.

find the vector<1,1>+<4,-3>

The normal vector to the surface is a radius at the point of interest.

You can find a missing denominator if you know something that the fraction is equal to. Then you can find the missing denominator through cross multiplication.