L = 156 cm
so L/2 = 156/2 = 78 cm
and so width = W = 36 cm more = 78+36 = 114 cm
Then perimeter = 2*(L+W) = 2*(156 + 114) cm = 2*270 cm = 540 cm
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The width is 10.5 cm.
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
Perimeter: Add the length of the four sides. Area: Multiply length x width.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
you need length and width length multiply width = area length + length + width + width = perimeter
Length + length + width + width = perimeter. Length + width x 2 = perimeter
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
You divide the perimeter by the width and you get the lenght
Length = (Perimeter - twice width) / 2
by appying 2l+2w
length 18 width 7
Perimeter = 2*(L + W).