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How many sum of the digit is nine?
To determine how many numbers have a sum of digits equal to nine, we consider the possible combinations of digits that add up to nine. These combinations include (9,0), (8,1), (7,2), (6,3), and (5,4). Therefore, there are five possible combinations of digits that sum up to nine.
How many 3 digit combinations numbers one through nine?
9!/6!, if the six different orders of any 3 digits are considered distinct combinations.
How many different ten digit number can be formed using the digits zero until nine excluding numbers starting with zero?
If you exclude numbers starting with zero then the first digit must be between 1 and 9 (i.e. 9 combinations). The remaining 9 digits can be any value between 0 and 9 (i.e. 10 combinations).So you can have 9x109 = 9,000,000,000 combinations.
How many four digit combinations can be made from the number nine example 1 2 3 39?
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
How many 3 digits no are there such that each digit is distinct to each other?
For the first digit, you have 9 options (1-9; the 3-digit number would not start with 0). For the second digit, you also have nine options (any digit from 0-9, except the digit used for the first digit). For this third digit, you have only eight options, since two digits are "forbidden", regardless of what digits you used first. That gives a total of 9 x 9 x 8 combinations.
How many five digit number combinations are there using the number five and nine?
Every one of the 5 digits can be either a 5 or a 9 so that means 2 choices for the first, 2 for the second digit, etc. There are 2^5 permutations of the numbers 5 and 9 in a 5 digits number.
What is the highest 9-digit number with no digits alike?
987654321 is the highest nine-digit number with no repeated digits.
What is the four digit number whose digits are reversed when multiplied by nine?
Find a four digit number whose digits will be reversed when multiplied by nine?
How many two digit even numbers can be composed from nine digits 1 2 3....9?
The first digit can be any one of the nine digits. For each of those . . .The second digit can be any one of four digits . . . 2, 4, 6, or 8 .Total number of possibilities = (9 x 4) = 36
What nine digit number is divisible by 11 and has no repeating digits?
There are many possible solutions. One such is 132486970
If you create a password using 4 numbers 0 through 9 how many different combinations are there without using the same number twice?
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
How many number combinations for 9 digits repeat allowed?
Well honey, if you're talking about 9-digit numbers with repeating digits allowed, you've got 10 options for each digit (0-9), so that's 10 choices for each of the 9 digits. So, the total number of combinations would be 10^9, which is a whopping 1 billion possible combinations. Hope that clears things up for ya!
