137, 173, 317, 371, 713, 731
Six combinations can be made.
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
35
589999999999
10,000 combinations.
Only 1. In a combination, the order of the numbers does not matter. So 102478 is the same combination as 104782 or 407812 etc.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
If each number can be used only once then there are just four: 2345, 2346, 2456 and 3456. There are no others because the order of the digits does not matter in combinations.
1000
None. If you sellect three numbers each time, you can only get combinations of 3, 6, 9, ect but never 4. Also, there seems to be some confusion between people and numbers!
There are only 5 distinct combinations of 4 numbers.(1234, 1235, 1245, 1345, 2345) C = 5! / 4!But there are 120 distinct combinations in distinct order (i.e. 24 ways to order each abcd).abcdabdcacbdacdbadbcadcb
35
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Just one. * * * * * Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
9999
All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you. The number of combinations is 9C3 = 9*8*7/3*2*1 = 84
589999999999