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Q: How many combinations can you get from a 3 digit code from 1 to 3?

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1296 or (6^4)

There are 1140 five digit combinations between numbers 1 and 20.

There are 5,461,512 such combinations.

There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.

There are 840 4-digit combinations without repeating any digit in the combinations.

Just 1.

I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.

There are 9C3 = 10*9*8/(3*2*1) = 120 of them.

7

100

There are 167960 9 digits combinations between numbers 1 and 20.

There are 167960 9 digits combinations between the numbers 1 and 20.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.

44

There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.

Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.

Any 5 from 59 = 5006386

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.

It depends first and foremost on how many digits in a phone number, but also on restrictions for various digit combinations. In the United States, the first digit of a 7-digit local phone number cannot be 0 or 1, and the first three digits cannot be certain reserved combinations like 411, 911, or 950. The result is that there are a bit less than 8 million possible phone numbers per area code.

1

-8

If the same 7 digits are used for all the combinations then n! = 7! = 7*6*5*4*3*2*1 = 5040 combinations There are 9,999,999-1,000,000+1=9,000,000 7-digit numbers.

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.