120.
Hargeisa somaliland 2522+4403988
There are 330 possible 5 note permutations derived from the chromatic scale.
There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
There is only one possible combination as a combination is the same no matter what the order is. There are 120 permutations, which is where the order does matter.
There are 5,273,912,160 permutations of 5 numbers out of 90.
There are 7893600 permutations.
Normally, there would be 5!=120 different permutations* of five letters. Since two of the letters are the same, we can each of these permutations will be duplicated once (with the matching letters switched). So there are only half as many, or 60 permutations.* (the correct terminology is "permutation". "combination" means something else.)
5!=2*3*4*5=120
There are 5*4*3 = 60 permutations.
6
5*4*3*2*1 = 120
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations