6
120
There are 330 possible 5 note permutations derived from the chromatic scale.
5! (Factorial).
There are 8P5 = 8*7*6*5*4 = 6720
There are 5,273,912,160 permutations of 5 numbers out of 90.
There are 7893600 permutations.
2520
There are 5P3 = 5!/2! = 5*4*3 = 60 permutations.
120.
There are 5*4*3 = 60 permutations.
Given the individual digits: 4, 6, 9, 1, and 3,the number of 4-digit permutations is (5! / 1!) = (5 x 4 x 3 x 2) = 120 .The number of combinations is [ 5! / (1!4!) ] = 5 .
6
You can simplify the problem by considering it as two different problems. The first involves consider the five-book chunk as a single book, and calculating the permutations there. The second involves the permutations of the books within the five-book block. Multiplying these together gives you the total permutations. Permutations of five objects is 5!, five gives 5!, so the total permutations are: 5!5! = 5*5*4*4*3*3*2*2 = 263252 = 14,400 permutations
The answer is 6P5 = 6!/(6-5)! = 6*5*4*3*2*1/1 = 720
120
It depends on how many digit you are choosing from.