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5 with remainder 39.
8 times with a remainder of 30
5 times
5 can go into 1000 200 times.
There are twenty numbers between 19 through 39, including 19 and 39. So the problem is 20 times 20 times 20 times 20 times 20. 320,0000
7 times. 39 times 7=273
7 times
3
5.875 times.
5 with remainder 39.
39 ÷ 7 = 5 with remainder 4.
5 times with a remainder of 4
5 times, with 20 left over.
8 times with a remainder of 30
39 ÷ 7 = 5 with remainder 4.
5.57 times.5 times with a remainder of 45 times with a remainder of 4
39 times with a remainder of 5 or 39.83 times.