6.71
Length AB is 17 units
8.8 Units
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
63 is composite
== == There are 20 possible opening moves in chess. There are eight pawns and each pawn has two possible moves. There are two knights and each knight has two possible moves. e4 King's pawn opening (B00) d4 Queen's pawn (A40) c4 English opening (A10) Nf3 Reti opening (A04) f4 Bird's opening (A02) b3 Nimzovich-Larsen attack (A01) Na3 Durkin's attack (A00) h4 Anti-Borg (Desprez) opening (A00) f3 Gedult's opening (A00) e3 Van't Kruijs opening (A00) d3 Mieses opening (A00) c3 Saragossa opening (A00) a4 Ware (Meadow Hay) opening (A00) a3 Anderssen's opening (A00) Nc3 Dunst (Sleipner, Heinrichsen) opening (A00) Nh3 Amar (Paris) opening (A00) h3 Clemenz (Mead's, Basman's or de Klerk's) opening (A00) g4 Grob's attack (A00) g3 Benko's opening (A00) b4 Polish (Sokolsky) opening (A00)
12
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
To find the length of segment AB, we can use the segment addition postulate, which states that the total length of a segment is equal to the sum of the lengths of its parts. Therefore, AB + BC = AC. Given that AC = 78 mm and BC = 29 mm, we can substitute these values into the equation to find AB: AB + 29 = 78. Solving for AB, we get AB = 78 - 29 = 49 mm.
12
The length of arc ACB is 57.2.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units