Width = X Length = 3X Four sides to the perimeter: x + x + 3x + 3x = 8x 8x = 22 x = 2.75 3x = 8.25 The length is 8.25.
Length = 3x - 2Width = x + 4Area = (length) times (width) = (3x - 2) (x + 4) = 3x2 + 10x - 8
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
angles dont have lengths, but degrees. it s an equilateral triangle ( length 3X the same, angle 3X 60°)
Width = X Length = 3X Four sides to the perimeter: x + x + 3x + 3x = 8x 8x = 22 x = 2.75 3x = 8.25 The length is 8.25.
Length AB is 17 units
8.8 Units
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Length = 3x - 2Width = x + 4Area = (length) times (width) = (3x - 2) (x + 4) = 3x2 + 10x - 8
The area of square is : 9.0
Using the distance formula the length of ab is 5 units
Using the distance formula the length of ab is 5 units
12
What is the area of a square with a side length of 4x^3
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
To find the length of segment AB, we can use the segment addition postulate, which states that the total length of a segment is equal to the sum of the lengths of its parts. Therefore, AB + BC = AC. Given that AC = 78 mm and BC = 29 mm, we can substitute these values into the equation to find AB: AB + 29 = 78. Solving for AB, we get AB = 78 - 29 = 49 mm.