0
The length is 3*sqrt(5) = 6.7082, approx.
Clark Rosenbaum
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What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
How can you express in radical form the length of the diagonal of a square whose sides are each 2?
Let 'a' and 'b' be the length of one side and diagonal of a square. Pythagorus's theorem as applied to a square: a^2 + a^2 = b^2. Substituting a = 2 into the equation, we have b^2 = 2^2 + 2^2 = 8. b = sqrt(8) = 2 * sqrt(2). Q.E.D. ===========================
Can you solve for b in the equation 12 equals negative 4 over 2 time negative 2 plus b?
12 = -4/2 * -2 + b 12 = -2 * -2 + b 12 = 4 + b 8 = b
If A (-2 -4) and B (-8 4) what is the length of the line?
Since you know that it is a parallelogram (not parallellogram!) you already know that the opposite sides are mutually parallel. All you need to do is to establish that any pair of adjacent sides are of equal length, or equivalently, the squares of these lengths are equal. The squared length of the line AB where A = (p,q) and B = (r,s) is (p - r)^2 + (q - s)^2.
Why does the area of a triangle quadruple when the sides are doubled?
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
If A is the point -2 -4 and B is -8 4 what is the length of AB?
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
If A (-2 -4) and B (-8 4) what is the length of line AB?
End points: (-2, -4) and (-8, 4) Length of line AB: 10
If A is the point -2 -4 and B is the point -8 4 what is the length of AB?
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
If A (-2 -4) and B (-8 4) what is the length of Ab?
Using the distance formula the length of ab is 5 units
If A 0 0 and B 8 2 what is the length of ?
(0,8)2 + (0,2)2 8(2=69 2(2=4 69+4=74√
What is the length of a right triangle if the base is 8 and hypotenuse is 10?
Use the Pythagorean theorem. a^2 + b^2 = c^2 a = base b = length c = hypotenuse 8^2 + b^2 = 10^2 b^2 = 10^2 - 8^2 b = sqrt(10^2 - 8^2) b = sqrt(100 - 64) b = sqrt(36 b = 6 ------------------the length
What is the length of the longest side of a triangle that has vertices at 4 -2 -4 -2 and 4 4?
a=8 b=6 c=10 answer is 10
If A(-2-4) and B(-8-4) what is the length of AB?
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
If a (0 0) and b (8 2) what is the length of ab?
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
If A squared plus B squared equals C squared and C equals 8 and A and B are the same length what are A and B?
4
How can you express in radical form the length of the diagonal of a square whose sides are each 2?
Let 'a' and 'b' be the length of one side and diagonal of a square. Pythagorus's theorem as applied to a square: a^2 + a^2 = b^2. Substituting a = 2 into the equation, we have b^2 = 2^2 + 2^2 = 8. b = sqrt(8) = 2 * sqrt(2). Q.E.D. ===========================
If A (10 4) and B (2 19) what is the length of AB?
Length AB is 17 units
