0.48
For each birth, you have two choices - either a boy or a girl. Then, the probability for a certain birth to obtain a choice is ½. Using Binomial Theorem, we have (10 choose 8)(½)8(½)² = 45/1024.
1/35
well it Will be even
Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
25
For each birth, you have two choices - either a boy or a girl. Then, the probability for a certain birth to obtain a choice is ½. Using Binomial Theorem, we have (10 choose 8)(½)8(½)² = 45/1024.
the answer is no because an estimated of 107 births that are boys and 100 of girls. That is the answer to that question.
1/35
Assuming that the chance of a woman giving birth to a boy or a girl is the same (in reality there's about 105 boys born for every 100 girls) then the probability of 22 of the same gender births *in a row* is: P=(0.5)^22=0.0000002384 or 1 in 4,194,304 It depends on the "when" of the question. If you point at a childless woman, and say "She will give birth to 22 children. What is the likelyhood that they will all be girls?" In that case the probability will be one in two-to-the-twenty-second. Pretty long odds. BUT, if you point at a woman with twenty one children, and ask "What are the odds that the next one will be a girl?" Then the answer is one in two. Make sense?
well it Will be even
Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.
This is a Binomial Probability; p=0.5, n=10 & x=7. Since you want the probability of exactly 7, in the related link calculator, after placing in the above values, P(x=7) = 0.1172 or 11.72%.
Assuming boys are equally as likely as girls, 125 boys would be expected. The probability of getting 140 or fewer boys is approximately 97.51%
bob was one of the 400 boys and 300 girls out of the uterus
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
4/8 x 3/5