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If x is an integer divisible by 3, is x squared divisible by 3?
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If x is an integer that is divisible by three then is x2 always divisible by 3?
Yes
An integer minus three times its reciprocal equals twenty six thirds What is the integer?
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
Which of the following is divisible by 3 and 6 but is not divisible by 4?
All numbers of the form 6+12x are, for all integer x.
What does divisible mean in maths?
X is divisible by Y if there is an integer Z such that X = Y*Z that is, Y will go into X without remainder.
Who do you factor x2 x-12?
14
What is a counter example to falsify If x is an integer divisible by 3 then x2 is an integer divisible by 3?
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
If x is an integer that is divisible by three then is x2 always divisible by 3?
Yes
If the domain of f(x)-x2 is integer values of x such that -3-x?
5
If x2 is an integer divisible by 3 then x is divisible by 3?
Yes. If x is not divisible by 3 then x leaves a remainder of 1 or 2 when it is divided by 3. That is, x is of the form 3y+z where z = 1 or 2. Then x2 = (3y+z)2 = 9y2 + 6yz + z2 = 3(3y2 + 2yz) + z2 The first part of this expression is clearly a multiple of 3, but z2 is not. Whether z = 1 or 2, z2 leaves a remainder of 1 when divided by 3.
An integer minus three times its reciprocal equals twenty six thirds What is the integer?
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
What is The square of a positive integer is 4 more than 3 times the integer?
x2=3x+4 x2-3x-4=0 (x-4)(x+1)=0 x=4 or x=-1 Since you specified a positive integer, the number in question is 4.
Which of the following is divisible by 3 and 6 but is not divisible by 4?
All numbers of the form 6+12x are, for all integer x.
Is 193 divisible by 3?
No, 250/3 = 83 remainder 1 3 is not a factor of 250 : the prime factors are 2 x 5 x 5 x 5 (2 x 53).
What does divisible meabn?
For an integer x to be evenly divisible by another integer y, x/y must also be an integer. Here are some examples: 4/2=2. 15/3=5. 18/6=3. From these examples, you can see that 4 is divisible by 2, 15 is divisible by 3, and 18 is divisible by 6. When two numbers are not evenly divisible by each other, you end up with a remainder, or fractional/decimal answer. Here is an example: 25/2 =12.5
Find all integer values of x that make the equation or inequality true x2 equals 9?
that would be limited to 3 and -3 for values of x
What is a grouping factor for polynomial x3 ax 3a 3x2?
x3 + ax + 3a + 3x2 = x (x2 + a) + 3 (a + x2) = x (x2 + a) + 3 (x2 + a) = (x2 + a)(x + 3) Checking the work: x3 + ax + 3x2 + 3a or x3 + 3x2 + 3a + ax = x2 (x + 3) + a (3 + x) = x2 (x + 3) + a (x + 3) = (x + 3)(x2 + a)
6 times an integer minus 5 equals the square of the integer. find the integer?
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
