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Q: Is 432 divisible by 2 3 5 6?
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Is the number 432 divisible by 2 3 5 6 9 10?

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.


Is 432 divisible by 2 3 5 9 or 10?

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.


Is the number 432 divisible by 2 3 5 6?

All except 5


Is 432 divisible by 2 3 4 5 6 9 and 10?

No.


Is 432 divisible by 5?

No, 432 divided by 5 is 86.4


Is 230 divisible by 2 3 and 5?

yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!


Can you tell if whether 432 is divisible by 2 3 4 5 6 9 10?

Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.


Is 5225 divisible by 3?

Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.


Is 672 divisible by 5 10 2 3?

It is divisible by 2 and 3. It isn't divisible by 5 and 10.


What number is divisible by 2 3 and 5?

30 is divisible by, and is the least common multiple of, 2, 3, and 5.


Is 800 divisible by 2 3 5 9 and 10?

It is divisible by 2, 5 and 10, but not 3 and 9.


What is divisible by 2 3 5?

One of the infinitely many integers divisible by 2, 3 and 5 is 3000.


Is 2390 divisible by 3 and 5?

2390 is not divisible by 3 but is divisible by 5. 2 + 3 + 9 + 0 = 14; 1 + 4 = 5: 5 is not divisible by 3, so 14 is not divisible by 3, so 2390 is not divisible by 3. 2390 ends with a 0, so 2390 is divisible by 5.


Is 1011 divisible by 2 3 5 9 10 or none?

It is divisible by 3.


Is 20 divisible by 2 3 5 9 or 10?

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.


What is 29178 divisible by 2 3 5 9 10?

29,178 is divisible by 2, 3 and 9, not by 5 or 10.


Can 534 divisble by 2 3 5 9 10?

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10


Is 290 divisible by 2 3 4 5 6 9?

It is divisible by 2 and 5


Is 534 divisible by 2 3 5 9 or 10?

It is evenly divisible by 2 and by 3.


Is 4320 divisible by 2 3 5 9 or 10?

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10


Is 475 divisible by 2 3 5 4 and 10?

475 is evenly divisible by 5, but not by 2, 3, 4, or 10.


Is 21 divisible by 2 3 or 5?

21 is not divisible by 2 nor 5, but it is divisible by 3. To be divisible by 2 the last digit must be even (one of {0, 2, 4, 6, 8}; the last digit 1 is not one of these, thus 21 is not divisible by 2 To be divisible by 3 sum the digits and if this total is divisible by 3, then so is the original number; the test can be repeated on the sum, so by repeatedly summing the digits of the totals until a single digit remains only if that single digit is 3, 6 or 9 is the original number divisible by 3. 21 → 2 + 1 = 3 which is divisible by 3 so 21 is divisible by 3. To be divisible by 5, the last digit must be 0 or 5. The last digit of 21 is 1 which is not 0 nor 5, thus 21 is not divisible by 5.


Is 20 divisible by 2 3 5 6 10?

It is divisible by 2, 5 and 10 but not the rest.


Is 621 divisible by 2 3 4 5 6 10?

It is only divisible by 3, and not 2, 4, 5, 6, or 10.


Is 325 divisible by 2 3 or 5?

325 is divisible by 5 leaving no remainder