Out of that list, 3 is the only factor of 429. But you knew that. You knew it couldn't be divisible by 2 or 6 because it's an odd number. You knew it couldn't be divisible by 5 because it doesn't end in 0 or 5 and you knew it couldn't be divisible by 9 because the digits don't add up to a multiple of 9.
2 and 3 yes, 5 no.
305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.
It is divisible by 2, 5 and 10 but not the rest.
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
no not by 10 as 216 ends in 6 not 0 same with 5 as does not end in 5 or 0 216 = 2 x 108 = 3 x 72 = 4 x 54 = 6 x 36 = 9 x 24 --------------------------------------- Last digit of 216 is even (one of {0, 2, 4, 6, 8}) so 216 is divisible by 2 6 + 1 + 2 = 9 which is divisible by 3 so 216 is divisible by 3 Last 2 digits are 16 which are divisible by 4, so 216 is divisible by 4 Last digit is not 0 nor 5, so 216 is NOT divisible by 5 216 is divisible by both 2 and 3 so 216 is divisible by 6 6 + 1 + 2 = 9, so 216 is divisible by 9 Last digit is not 0, so 216 is NOT divisible by 10 216 is divisible by 2, 3, 4, 6, 9. 216 is NOT divisible by 5 nor 10.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
All except 5
No.
No, 432 divided by 5 is 86.4
yep it is because 2 is divisible by 2 and 3 is divisible by 3 and 0 is divisible by 5 have fun suckers!
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
Is 5225 divisible by 3? A number is divisible by 3, if the sum of its digits is evenly divisible by 3. 5 + 2 + 2 + 5 = 14. Since 14 is not divisible by 3, neither is 5225.
535 is not divisible by 2, 3, 9, or 10. It is an odd number, so it cannot be divisible by 2. The sum of its digits (5 + 3 + 5 = 13) is not divisible by 3, and it does not end in 0 or 5, which means it is not divisible by 10. However, 535 is divisible by 5, as it ends with a 5.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.