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(tanx+cotx)/tanx=(tanx/tanx) + (cotx/tanx) = 1 + (cosx/sinx)/(sinx/cosx)=1 + cos2x/sin2x = 1+cot2x= csc2x
This is a pythagorean identity.
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Cos2x equals 1 minus tan squared x divide by1 plus tan squared x?
The Answer is 1 coz, 1-Tan squarex = Cot square X. So cot square x divided cot square x is equal to 1
Sec squared theta plus tan squared theta equals to 13 12 and sec raised to 4 theta minus tan raised to 4 theta equals to how much?
It also equals 13 12.
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
How do you find the length of a leg on a right triangle when one leg and the slope of the hypotenuse is given?
Use tangent. Your equation will be tan(slope of hypotenuse) = opposite side / adjacent side. it's easier if you just do A squared plus b squared equals c squared. Then subtitute the numbers gived in.
How would you solve the integral of 1 plus tan2x plus tan squared 2x?
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
Csc divided by cot squared equals tan multiplied by sec?
Yes.
What is Sin squared x - Cos squared x divided by 1 - Tan squared x equals cos squared x?
22
Cos2x equals 1 minus tan squared x divide by1 plus tan squared x?
The Answer is 1 coz, 1-Tan squarex = Cot square X. So cot square x divided cot square x is equal to 1
Sec squared theta plus tan squared theta equals to 13 12 and sec raised to 4 theta minus tan raised to 4 theta equals to how much?
It also equals 13 12.
How can you verify 1 plus tan theta divided by 1 minus tan theta equals cot theta plus 1 divided by cot theta minus 1?
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
What is the relation of the forms y equals Psinx plus Qcosx and y equals Asin of x plus c?
A = Root (Q squared plus P squared) C = 90 + tan inverse P/Q ... I think lol just worked it out just now =w=
Tan 9-tan 27-tan 63 plus tan81 equals 4?
4
Tan3x plus tanx equals 2tan2x?
Tan
How do you find the length of a leg on a right triangle when one leg and the slope of the hypotenuse is given?
Use tangent. Your equation will be tan(slope of hypotenuse) = opposite side / adjacent side. it's easier if you just do A squared plus b squared equals c squared. Then subtitute the numbers gived in.
How would you solve the integral of 1 plus tan2x plus tan squared 2x?
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
What is sec squared theta times cos squared theta minus tan squared theta?
Tan^2
Tan theta plus cot theta equals 2csc2 theta?
Yes, it is.
