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Since the average of the three integers will be 114/3 = 38, and the three numbers are consecutive, the numbers will be 36, 38 and 40.

Another way to do this problem using algebra is to let the first integer be n, then the next two are n+2 and n+4. Their sum is 3n+6 and it equals 114

So 3n+6=114 and


so n=36

then next two numbers must be 38 and 40 since they are consecutive even integers.

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โˆ™ 2010-06-15 06:01:53
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Q: The sum of three consecutive even integers is 114?
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