The multiples of 3 are elements of the infinite set of numbers of the form 3*k where k is an integer.
The digital root is the sum of all the digits in an integer, with the process repeated if required. The digital root of all multiples of 3 are themselves multiples of 3. Their fully reduced values are 3, 6 or 9.
3s + 1
135=3s +15 120=3s 40=s
28 3s
3S Facility simply means sales, services and spares
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
4 3s = 4*3 = 12, which is a rational number.
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
2h2s + so2 - 2h20 + 3s
12r - 15s - r + 3s = 11r -12s
The equation 4R + 3s + 2r = 6r + 3s is an example of the distributive property of addition, where the term 4R is being distributed over the sum of 2r and 6r. To see this more clearly, we can rewrite the equation as: 4R + 3s + 2r = (4R + 6r) + 3s Notice how the terms 4R and 6r are combined and the distributive property allows us to simplify the left-hand side of the equation.