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What pattern do you see in multiples of 3s?
The digital root is the sum of all the digits in an integer, with the process repeated if required. The digital root of all multiples of 3 are themselves multiples of 3. Their fully reduced values are 3, 6 or 9.
What pattern do you see with 3s and 6s?
The pattern with 3s and 6s is that 6 is a multiple of 3, meaning every 6 can be expressed as 2 times 3. Additionally, if you list the multiples of 3 (3, 6, 9, 12, etc.), every second multiple is also a multiple of 6. This creates a predictable relationship where 6s appear in the sequence of 3s at regular intervals.
What is 3s plus 1?
3s + 1
What is 135 equals 3s plus 15?
135=3s +15 120=3s 40=s
how many 3 are in 6037234789333333333333333333333333363?
28 3s
What is a 3S facility?
3S Facility simply means sales, services and spares
How many 3s go into 140?
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
How do you do -7 equals 3s-1?
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
How do you solve an inequality with a negative coefficient?
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
What is 4 3s written as a rational number?
4 3s = 4*3 = 12, which is a rational number.
Balance 2H2S plus SO2-H2o plus 3s?
2h2s + so2 - 2h20 + 3s
What is 12r-15s-r plus 3s?
12r - 15s - r + 3s = 11r -12s
