depends if you are allowed to repeat a number or not. If you are it's 6 times 6 times 6 times 6 = 1296 If not then it's 6 times 5 times 4 times 3 = 360
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
16
The greatest 4-digit number that is divisible by 16 is 9984
To form a 3-digit odd positive integer using the digits 2, 3, 4, 5, and 6, the last digit must be an odd number. The available odd digits are 3 and 5. If we choose 3 as the last digit, we can use any of the remaining digits (2, 4, 5, 6) for the first two digits, giving us 4 options for the first digit and 4 options for the second digit (since we can repeat digits). This results in (4 \times 4 = 16) combinations. Similarly, if we choose 5 as the last digit, we again have 4 options for the first digit and 4 for the second, resulting in another (4 \times 4 = 16) combinations. Thus, the total number of odd 3-digit integers is (16 + 16 = 32).
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
16
The greatest 4-digit number that is divisible by 16 is 9984
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.
To form a 3-digit odd positive integer using the digits 2, 3, 4, 5, and 6, the last digit must be an odd number. The available odd digits are 3 and 5. If we choose 3 as the last digit, we can use any of the remaining digits (2, 4, 5, 6) for the first two digits, giving us 4 options for the first digit and 4 options for the second digit (since we can repeat digits). This results in (4 \times 4 = 16) combinations. Similarly, if we choose 5 as the last digit, we again have 4 options for the first digit and 4 for the second, resulting in another (4 \times 4 = 16) combinations. Thus, the total number of odd 3-digit integers is (16 + 16 = 32).
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
16. There are two choices for the first digit (3 and 6). For either choice of first digit there are two choices for the second digit, and so on. 2 x 2 x 2 x 2 = 16.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.