11
4x2 plus 3=11
4x2 + 1 + x2 + 3 = 5x2 + 4
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
It is 4x2 + 426x + 630.
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
I assume you mean factors for 4x2+10x+6.(2x+3)(2x+2).
4*2=8+3=11
No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
(2x + 3)(2x + 3)