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Yes: The intersection is at one end of each side. This is true for a diagonal of any quadrilateral.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
A parallelogram is anything from a square to a rectangle. As long as it has parallel sides, then it is a parallelogram. If you're thinking of a rhombus, then it has diagonal sides.
a squished rectangle
A parallelogram has two diagonals the same as all 4 sided quadrilaterals
Yes: The intersection is at one end of each side. This is true for a diagonal of any quadrilateral.
Because the diagonals of a rhombus intersect each other at 90 degrees whereas in a parallelogram they don't
two congruent triangles
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
Parallelogram is the answer you Knowas well as rectangleAlso a square, and a rhombus
A parallelogram is anything from a square to a rectangle. As long as it has parallel sides, then it is a parallelogram. If you're thinking of a rhombus, then it has diagonal sides.
a squished rectangle
A parallelogram has two diagonals the same as all 4 sided quadrilaterals
the diagonal in a paralleogram is not equal but the diagonals in the rectangle are congruent this is because the opposite sides of a parallelogram and rectangle are same parallel to each other but the adjacent sides of a parallelogram is not perpendicular where as the adjacent sides of rectangle is perpendicular to each other.
No. Most do not.
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If you draw a diagonal line from corner to corner of a parallelogram, that is a line of symmetry.