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What does this x2 4x 1?

Updated: 8/16/2019
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12y ago

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Something other than pandas.

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Q: What does this x2 4x 1?
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X2 plus 1 divided by 2x4 plus 4x3 -x2 plus 4x-3?

You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)


How do you solve x2 plus 4x equals 1?

x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i


What is the factor of x3 plus x2 plus 4x plus 4?

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)


What is x2 plus 4x plus 3 factorised?

x2 + 4x + 3 = (x + 1)(x + 3)


What is 4x-x2?

4x-x2 = 2


How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?

Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8


Which equation has the solution set 1 and 3?

The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0The equation is (x - 1)*(x - 3) = 0 or x2- 4x + 3 = 0


2x equals x2 plus 4x-3?

2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0


How do you graph a parabola?

y=x2+4x+1


What is X2 divided by -4x?

6


Solve x2 plus 4x plus 3 equals 0?

x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}


What must be added to 3x-7 to make x2 4x -1?

x2 + x + 6