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Q: What is 3c plus 5c plus c simplified?

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The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b

(5c - 2)(c +1)

The simplified answer is: 4c+2b

3c - 12 + 5c = 12Combine the 'c' terms on the left side:8c - 12 = 12Add 12 to each side:8c = 24Divide each side by 8:c = 3

(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)

20c + 5 = 5c + 65 Divide through by 5: 4c + 1 = c + 13 Subtract c from both sides: 3c + 1 = 13 Subtract 1 from both sides: 3c = 12 Divide both sides by 3: c = 4 20c + 5 = 5c +65 20c - 5c= 65 - 5 15c = 60 15c/15 = 60/15 c = 4 (alternative method)

3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c

3c

c2 + 5c + 6 = (c + 2)*(c + 3)

6c.

2b+3c

4a + 3c - 2b - c + a - b = 5a - 3b + 2c

80°F = 262/3°C To convert Celsius to Fahrenheit, the formula is F = 9/5C + 32. If the Fahrenheit reading is 3 times the Celsius reading then F = 3C, so 3C = 9/5C + 32 : 6/5C = 32 : C = 262/3. Then F = 3C = 3 x 262/3 = 80

4c+2 = 3c+9 4c-3c = 9-2 c = 7

If: 3c = 6Then: c = 2

c=-7,c=-3,c=2,c=5

2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4

4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2

4c2 + 5c + 2c = 4c2 + 7c = c(4c + 7)

3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4

17-3= 4c+3c c=2

You can't tell a thing about -5c+9 until you know what 'c' is. And every time 'c' changes, -5c+9 changes.

C - 6C + 7 = -5C + 7

That factors to (b + 3)(a + c)

(c + 3)(c^2 - 3c + 9)