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What equations are equivalent to 3p(p plus 2)?
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the answer to -3p-5 - 7p plus 2p-18 - 6?
The expression can be simplified to: -8p--29
What is the perpendicular bisector equation of the line segment of p q and 7p 3q?
In its general form it works out as: 3px+qy-12p2-2q2 = 0Improved Answer:-Points:(p, q) and (7p, 3q)Slope: q/3pPerpendicular slope: -3p/qMidpoint: (4p, 2q)Equation: y-2q = -3p/q(x-4p) => yq = -3px+12p2+2q2Perpendicular bisector equation in its general form: 3px+qy-12x2-2q2 = 0
How do you simplify (-5q2p)3?
minus a minus is plus, so it's -8 + 3, which is 3 - 8, or -5
What is p plus q and 2p?
It is an expression that can be simplified to: 3p+q
What is 3p-2-29?
They are three terms of an expression that can be simplified to: 3p -31
What is -2(-3)(-4) simplified?
They are three terms of an expression that can be simplified to: 3p -31
What equations are equivalent to 3p(p plus 2)?
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
Find 2p2 plus 3p - 4 less - 2p2 - 3p plus 4.?
This expression when simplified comes to: 0
How do you solve 1.50p plus 2.50p plus 3p This is a simplifying algebraic expressions and add subtract integer problem?
It is: 1.50p+2.50p+3p = 7p when simplified
What is the perpendicular bisector equation of the line joined by the points of p q and 7p 3q on the Cartesian plane?
Points: (p, q) and (7p, 3q) Midpoint: (4p, 2q) Slope: q/3p Perpendicular slope: -3p/q Perpendicular bisector equation:- => y-2q = -3p/q(x-4p) => qy-2q^2 = -3p(x-4p) => qy-2q^2 = -3px+12p^2 => qy = -3px+12p^2+2q^2 In its general form: 3px+qy-12p^2-2q^2 = 0
What is the answer to -3p-5 - 7p plus 2p-18 - 6?
The expression can be simplified to: -8p--29
What is the sum of the quotient of p and 14 and the quotient of q and 3?
p/14 + q/3 = (3p + 14q)/ 42
How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q) Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope = (3q-q)/(7p-p) = 2q/6p = q/3p Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1) y-2q = -3p/q(x-4p) y-2q = -3px/q+12p2/q y = -3px/q+12p2/q+2q Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:- 3px+qy-12p2-2q2 = 0
What is 3pq take away 6p squared?
3pq - 6p2 = 3p*(q - 2p)
What is 3p plus 4q if p is 5 and q is -2?
(3*5)+(4*-2) = 7
