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An algebraic expression
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2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is the 3 consecutive integers added to get 41?
44
3x plus 4x plus 6 equals 41?
x=5
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
What is 5x plus 17 equals 2x plus 41?
3x = 24, x = 8
2x-6x plus 3x equals -41?
2x - 6x + 3x = -412x - 3x = -41-1x = -41x = 41
What is 3x-x44?
3x-x44 = -41
What is the 3 consecutive integers added to get 41?
44
If 2x 3y 17 and 3x 4y 24 then 5x 7y?
41
If g(x) 3x plus 1 evaluate g(-14).?
It is -41.
3x plus 4x plus 6 equals 41?
x=5
What is the answerThe sum of triple a number and 5 is 41?
Let the number be x and so if 3x+5 = 41 then x = 12
What is the value of c if the discriminant of negative 2x squared minus 3x plus c is 41 and what is the standard form of the expression i over 2 plus i?
Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i
What is 5x plus 17 equals 2x plus 41?
3x = 24, x = 8
How do you solve 3x-28-5x equals 5x plus 13?
3x-28-5x=5x+13 Let us first solve the variables -2x-28=5x+13 Transposing -28 to Right hand side -2x=5x+13+28 -2x=5x+41 Transposing 5x to left hand side -2x-5x=41 -7x=41 equation 1 x=41/-7 x=-41/7 Hence the required answer is -41/7. You can verify it by substituting the value of x in the given equation. If Right hand side is equal to Left hand side the answer is right. Let us verify Substituting the value of x=-41/7 in the given equation1 -7(-41/7)=41 -7 X -41/7 =41 41=41 LHS=RHS Hence Verified
What three consecutive numbers added together equal 120?
The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120
What are three consecutive odd integers that have a sum of 123?
39, 41, 43 Let x represent the smallest of these numbers. From the problem, we know x+(x+2)+(x+4)=123 Solving for x: 3x+6=123 3x=117 x=117/3=39 So our integers are: 39, 41, 43
