0
6-4y = 2
What else can I help you with?
Divide 40x over 64y by 5x over 8y?
140x / 64y divide 5x/8y = > 40x/64y X 8y/5x Note the change of sign and the inversion of the Right hand fraction. Cancel down by '5x' 8/64y X 8y/1 Cancel down by '8y' 8/8 X 1/1 = 8/8 = 1 The answer!!!!
What is the product of (9x-8y)(9x 8y)?
If you mean (9x-8y)(9x+8y) then it is 81x^2 minus 64y^2
Is y6 plus 8y3 plus 64y a trinomial with a constant term?
No.
What is 64y cubed plus 1?
You can't simplify it any further without a value for y.
How do you solve 81x2 144xy 64y2?
To solve the expression ( 81x^2 + 144xy + 64y^2 ), you can recognize it as a perfect square trinomial. It can be factored as ( (9x + 8y)^2 ). Thus, the solution is ( (9x + 8y)^2 ).
X plus 8y equals 22 -8x-2y plus 10?
8x + 64y = 176 Add: 62y = 186 so y = 3 and x = -2 This assumes you mean "equals 10", not "plus 10"
How do I solve for y the linear equations 8x-7y equals 7 and 7x equals 8y equals 8?
8x - 7y = 7 (A)7x + 8y = 8 (B)7*(A): 56x - 49y = 498*(B): 56x + 64y = 648*(B)-7*(A): (64+49)*y = 64-49=> 113y = 15=> y = 15/113
What two numbers are the product of 900 but there sum equal 64?
ANSWER: The two numbers required are not whole numbers. These are 43.135 and 20.865.Solution 1:Assuming you want whole numbers:Prime factorization for 900 is2 x 2 x 3 x 3 x 5 x 5You cannot combine these in any way to have a sum that is 64. You can with 65, but not 64.Solution 2:Let:x = first numbery = second numberx * y = 900 (Equation 1)x + y = 64x = 64 - y (Equation 2)Substitute Eq. (2) in Eq. (1):x * y = 900(64 - y) y = 90064y - y2 = 900- y2 +64y - 900 = 0 (Equation 3)multiply Eq. (3) by -1y2 - 64y + 900 = 0using quadratic equation:y1 = 43.135 y2 = 20.865Therefore, the two numbers are 43.135 and 20.865
What two numbers multipy to equal 900 and the sum of the two numbers equals 64?
Solution 1: Prime factorization for 900 is2 x 2 x 3 x 3 x 5 x 5You cannot combine these in any way to have a sum that is 64. You can with 65, but not 64.Solution 2:Let:x = first numbery = second numberx * y = 900 (Equation 1)x + y = 64x = 64 - y (Equation 2)Substitute Eq. (2) in Eq. (1):x * y = 900(64 - y) y = 90064y - y2 = 900- y2 +64y - 900 = 0 (Equation 3)multiply Eq. (3) by -1y2 - 64y + 900 = 0using quadratic equation:y1 = 43.135 y2 = 20.865Therefore, the two numbers are 43.135 and 20.865
Find a possible formula for the quadratic function whose graph has vertex left parenthesis 8 comma 2 right parenthesis and y intercept negative 11?
Using the vertex (h, k) the equation of the quadratic would be: y = a(x - h)² + k → y = a(x - 8)² + 2 → y = a(x² - 16x + 64) + 2 → y = ax² -16ax + 64a + 2 Using the y-intercept of (0, -11): -11 = a 0² - 16a 0 + 64a + 2 → 64a = -13 → a = -13/64 Thus the quadratic could be: y = (-13/64)x² - 16(-13/64)x + 64(-13/64) + 2 → y = (-13/64)x² + (13/4)x - 11 Or, removing the fractions: 64y = -13x² + 208x - 704
How do you foil -y32x2y-4xy2?
You can't exactly FOIL it because you don't have a problem in the form of (3x + 2)(4x - 6) Frankly, I don't understand exactly what question you are trying to solve, so I'll give you a couple of examples that might help. (-y32) times (2y - 4xy2) turns into: ((-1)(y32) times 2y) plus ((-1)(y32) times ((-1)(4xy2)) which becomes -2y33 plus 4xy34 which would be more often expressed as 4xy34 - 2y33 Perhaps you meant something more like this: (-y times 32) times (2y - 4xy2) turns into: (-32y) times (2y - 4xy2) which becomes (-y times 2y) + (-y times -4xy2) + (32 times 2y) + (32 times -4xy2) which becomes -2y2 + 4xy3 + 64y - 128xy2 which is 4xy3 -128 xy2 - 2y2 + 64y I'm sure if I'm gotten it wrong, someone will straighten it out. Also, if this doesn't help, please fix up the original question so it can be answered properly.
If a number is twelve less than four times another number their difference is fifty-one what are the numbers?
First off the original equation would beX - 12 = 4*yThis equations is broken down like this: a number (x) is twelve less (-12) than (=) four times (4 * ) another number (y)The second equation comes from "Their difference (another term for subtraction) is 51"x-y = 51The easiest way to solve this problem would be to solve a system by substitution.In the equation x-y = 51, add y to both sidesThis would come out to x = y+ 51Then you take this equations and substitute it in for x into the other equationy + 51 - 12 = 4y-4 from both sides51 - 12 = 3ycombined like terms39 = 3yy = 13Then plug back into the equationx -12 = 13 * 4simplify 13 * 4x - 12 = 52add 12 to both sidesx=64y = 13andx=64
