u15 = u7 + (15-7)*d = 2.33 + 8*(-0.67) = -3.03
15(1)
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
There are two ways to say the general rule. They both mean exactlythe same thing, and they both generate the same sequence:1). Starting with 15, each new term is 3 less than the one before it.2). The nth term of the sequence is [ 18 - 3n ] or [ 3 times (6 - n) ].
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
The nth term is -7n+29 and so the next term will be -6
15(1)
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
yes it is
There are two ways to say the general rule. They both mean exactlythe same thing, and they both generate the same sequence:1). Starting with 15, each new term is 3 less than the one before it.2). The nth term of the sequence is [ 18 - 3n ] or [ 3 times (6 - n) ].
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
Well, darling, the nth term for this sequence is 8n + 7. You just add 8 to each term to get the next one, simple as that. So, if you want the 100th term, just plug in n=100 and you'll get 807. Easy peasy lemon squeezy!
The sequence 3, 7, 11, 15 is an arithmetic sequence where each term increases by 4. The recursive rule can be expressed as ( a_n = a_{n-1} + 4 ) with ( a_1 = 3 ). The explicit rule for the nth term is ( a_n = 3 + 4(n - 1) ) or simplified, ( a_n = 4n - 1 ).
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
The next term is: 15+4 = 19 The nth term is: 4n-5