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What is t2 plus 11t plus 10?
If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized
What is the remainder when t plus 1 is divided into t5 plus t4 plus t3 plus t2 plus t plus 1?
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
How do you factor t2 plus 6t-7?
(t + 7)(t - 1)
How do you factor T2 plus 4T?
T(t + 4)
What is brackets t plus 2 to the power of 2?
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
What is t2 plus 11t plus 10?
If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized
What is the remainder when t plus 1 is divided into t5 plus t4 plus t3 plus t2 plus t plus 1?
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
How do you factor t2 plus 6t-7?
(t + 7)(t - 1)
How do you factor T2 plus 4T?
T(t + 4)
What is the answer to t2 plus t plus 3 equals 0?
If t2 + t + 3 = 0 then[moving the 3 to the other side of the equation]t2 + t = -3[adding a value to both sides of the equation allowing us to easily factor the expression - i.e. completing the square]t2 + t + 1/4 = -3 + 1/4[factoring the expression: t2 + t + 1/4 factors to (t + 1/2) (t + 1/2) i.e. (t + 1/2)2 ](t + 1/2)2 = -3 + 1/4(t + 1/2)2 = -2.75[now square root each side]t + 1/2 = -2.751/2t = -2.751/2 - 1/2[the square root of -2.75 is equal to the square root of 2.75 * the square root of -1. The square root of -1 is an imaginary number represented by the letter "i"]t = (2.751/2 * -11/2) - 1/2t = (2.751/2 * i) - 1/2[the square root of 2.75 has two answers (+ and -) which will provide the two roots to the quadratic]t = + or - 1.658i - 1/2 (to 3 decimal places only)To solve this equation we have used the technique of "completing the square" and have made use of the imaginary number "i".This equation does not have real roots as it involves the square root of a negative number and so this is the only way in which we can answer the question.
What are the factorsof 81?
t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)
Factor 77-18T plus T2?
(t - 7)(t - 11)
What is brackets t plus 2 to the power of 2?
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
What is the integral of 2 times 1-x dx with limits 0 to t?
,/` 2(1 - x) dx,/` 2 - 2x dx2x - x2 ...evaluated from 0 to t gives us...2t - t2 - [2(0) - (0)2]2t - t2
T2 minus 59t plus 54 minus 82t2 plus 60t?
t2 - 59t + 54 - 82t2 + 60t = - 81t2 + t + 54
Derive expression of time dilation in relativity?
In order to derive this, we have to consider two systems S & S'.Let S' be moving with a velocity v w.r.t S in the positive direction of X-axis. Clock too!! has to be included as the word dilation means to lengthen at time. So,suppose a clock is situated in the system S at position x and gives signs of interval ∇t, i.e., ∇t = t2-t1 ___________________(i) If this interval is observed by an observer in system S',then interval ∇t' recorded by an observer is given by ∇t' = t1'-t2' _____________(ii) From Lorentz transformation, t1' = t1-(vx/c2)/(1-v2/c2)1/2_____________(iii) and t2' = t2-(vx/c2)/(1-v2/c2)1/2 ______________(iv) Substituting the values of t1' and t2' from equations (iii) & (iv) in (ii), we get ∇t' =t2-(vx/c2)/(1-v2/c2)1/2 - t1-(vx/c2)/(1-v2/c2)1/2 = t2-vx/c2 - t1+ vx/c2/(1-v2/c2)1/2 = t2-t1/(1-v2/c2)1/2 = ∇t/ (1-v2/c2)1/2 So, ∇t' = ∇t/ (1-v2/c2)1/2, where ∇t'>∇t. Hey buddies,just imagine the graph yourself..!! ()() (':') (")(") IZ
What is the answer to t squared plus t minus 42?
t2+ t - 42 it can't be simplified anymore
