it VARIES! --- 10by10by10by10=25sqrt3
Area = 50 cm2
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
A = 48 units2
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
Area of Rhombus = length of first diagonal x length of second diagonal / 2 / means divided by So for your problem: Area of Rhombus = 10 feet x 14 feet / 2 = 70 square feet
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
It is: 10+10+10+10 = 40 cm
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
Area of the rhombus: 0.5*8*10 = 40 square feet
The garden's diagonal is 10 meters.
The area of square is : 100.0
Area = 50 cm2
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50