It is negative 2.
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
10n + 1
This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 10.
15(1)
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is constant. For example, the sequence 2, 5, 8, 11, 14 has a common difference of 3. Another example is 10, 7, 4, 1, which has a common difference of -3. In general, an arithmetic sequence can be expressed as (a_n = a_1 + (n-1)d), where (a_1) is the first term and (d) is the common difference.
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
The sequence provided is an arithmetic sequence where the first term is 3 and the common difference is 2. The formula for the nth term of an arithmetic sequence is given by ( a_n = a_1 + (n-1)d ), where ( a_1 ) is the first term and ( d ) is the common difference. For the 10th term, ( a_{10} = 3 + (10-1) \times 2 = 3 + 18 = 21 ). Thus, the 10th term of the sequence is 21.
10n + 1
This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by 10.
15(1)
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
This is an arithmetic sequence with t1 = 1 and the common difference d = -18.The nth term of an arithmetic sequence is given by the formula:tn = t1 + (n - 1)d (substitute 10 for n, 1 for t1, and -18 for d)t10 = 1 + (10 - 1)(-18) = 1 + 9(-18) = 1 - 162 = -161Thus the 10th number of the sequence is -161.
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
Nope, bc the common difference is not constant ( linear) its goes up +1, +5, +2, therefore, again, it's not constant
Arithmetic- the number increases by 10 every term.
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).