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The equation for the axis of symmetry is?
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
How do you find the gradient of a quadratic equation?
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
How do you get the x and y intercept of 3x 4y -24?
The x-intercept is the point where the line crosses the x-axis. 'y' is zero at every point on the x-axis. So to find where the line crosses the x-axis, make 'y' zero, and solve the equation for 'x'. -- The y-intercept is the point where the line crosses the y-axis. 'x' is zero at every point on the y-axis. So to find where the line crosses the y-axis, make 'x' zero, and solve the equation for 'y'. This is the central idea that the following answer calls "zero out". =========================================================X and Y intercepts
Find the equation of a line that is parallel to the y-axis?
In 2-dimensional co-ordinate geometry, a line parallel to the y axis has the equation x = c where c is a constant.
How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
How do you find the zeros in an equation by looking on a graph?
They are all the points where the graph crosses (or touches) the x-axis.
How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
How can you find the differential equation of a family of circles passing through the origin and having centers on the x axis?
To find the differential equation of a family of circles passing through the origin and having centers on the x axis one needs to have a variable to compare it to. To best find this answer one might enlist the help of a math professor as well.
Find the equation of the line perpendicular when the slope is zero?
when the slope is 0, the graph is a horizontal line on the x axis so the y axis is perpendicular to it, which can be written x=0
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
How do you find the solution of a quadratic equation graphically?
You write the equation in such a way that you have zero on the right side. Then you graph the expression on the left side of the equal sign, and check where it touches the x-axis. Note that this method works for most common equations.
How do you find the equation for Y intercept?
On the y-axis, x=0. Take the equation you have, set x=0, solve what's left for 'y'. That's the y-intercept.
