Study guides

☆☆

Q: What is the first derivative of e raised to the power of x?

Write your answer...

Submit

Still have questions?

Related questions

The derivative of ex is ex

d/dx e3x = 3e3x

e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)

e raised to the 0 power is 1

I assume you mean 27 times e to the power x. 1) You take out the constant out. So, the derivative is 27 times the derivative of (e to the power x).2) You use the rule for the exponential function.

That's because powers that involve the power "e", and logarithms to the base "e", are simpler than other powers or logarithms. For example: the derivative of ex is ex, while a derivative with other bases is more complicated; while the derivative of the natural logarithm (ln x, or logex) is 1/x.

1/e

d/dx (e-x) = -e-x

e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.

y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0

e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.

y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1

People also asked